Edit View History Bookmarks People Window Help s/DChapter 10 Homework Apiece of

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Edit View History Bookmarks People Window Help s/DChapter 10 Homework Apiece of sodium metal rx bubble mheducation.com/hm.tpx connect EK sections: Ch CHEMISTRY work Question 9 (of 12) points 4 attermpts left Check my work Enter your answer in the provided box. The volume of a sample of pure HCl gas was 179 mL at 25°C and 103 mmHg. It was completely dissolved in about 50 mL of water and titrated with an NaOH solution; 11.3 mL of the NaOH solution was required to neutralize the HC1. Calculate the molarity of the NaOH solution. 8b8adb..pof 2ade688b 34d8b8adb. pat cBook Pro

Explanation / Answer

Solution-

Using the formula PV = nRT
(103 Torr) (0.179 Litres) = n (62.36 L-Torr/mol-K)(298K)
n = 9.21*10^-4 moles of HCl

Because of all of the HCl against the NaOH
by the equation:
1 HCl & 1 NaOH --> 1 NaCl & 1 H2O
9.21*10^-4 moles of HCl reacts with an equal number of moles of NaOH = 9.21*10^-4 moles of NaOH


Now let us find the molarity of the 11.3 ml:
9.21*10^-4 moles of NaOH / 0.0113 Litres of NaOH = 0.0815 Molar

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