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For Trans-Chalcone (614-47-1) 13C NMR , labels for carbon must be assigned begin

ID: 1029263 • Letter: F

Question

For Trans-Chalcone (614-47-1) 13C NMR , labels for carbon must be assigned beginning with a from upfield to downfield (i.e., a is smallest ppm) and the carbon types determined.

I've already given labels and chemical shifts on the structure and table (I think they are correct but at the b, c, d, and e labels, they seem really close together and I'm not sure if I can just count all of them under one label). The carbon types are also unknown. Thanks for the help and explanation.

6) (g (c 200 180 160 140 120 100 80 640 20 ppm Obtained at 25 MHz using Chloroform-D Note: Assign carbon labels beginning with a from upfield to downfield (i.e., a is smallest ppm and h is the largest ppm)

Explanation / Answer

What you have assigned is correct, and no need to count a, b,c,d and e as seprate label, since each giving seprate signal

And all carbons are sp2 hybridized since all carbon having double bond

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