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l openvellum.ecolleae.com/course.html2courselds14586367&OpenVelumHMAC; 6191b310e24c5343deaob9d2d Chrome - MasteringChemistry: Post Lecture Homework Chapter 04 e Secure https:/session.masteringchemistry.com/myct/itemView?assignmentProblemiD-98083645 You may want to reference (Pages 111-113) Section 3.9 while completing this problem. Part A . ) oxide contains 578 g of iron? Iron(III) oxide is 69.94 % iron by mass What mass (in grams) of iron(III Express the mass to three significant figures and include the appropriate units ValueUnits

Explanation / Answer

Answer:

A substance's percent composition is defined as how many grams of each element in 100 g of given compound.

Given, a percent composition of Fe2aO3, 69.94% iron by mass means that for every 100 g of iron(III) oxide, Fe2O3, you get 69.94 g of iron.

Therefore, for 57.8 g of iron, the mass of Fe2O3 is

=57.8 g Iron X(100g Fe2O3/69.94 g Iron)

=82.6 g of Fe2O3.

The mass of Fe2O3=82.6 g.

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