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Safari File Edit View History Bookmarks Window Help saplinglearning.com EM 102-Spring18-T Texas A&M; University at Galveston-CHEM 102-Spring18-TOWNSEND: HW 12 Sapling Learning Jump to... Attempts Score 3/19/2018 06:00 PM 62/100 3/18/2018 03:43 PM -Print Calculator Peride Table Question 11 of 23 Incomect Sapling Learning 90 10 3 11 2 121 13 2 14 3 5 5 80 At a certain temperature, 0.640 mol of SOs is placed in a 4.50-L container At equilibrium, 0 200 mol of Oz is present. Calculate K 90 K0207 There is a hint available View the hint bottom divider bar divider bar again to hide the hint. The Close OPrevious Give Up & View Solution 9Chock Answer 0Next 18

Explanation / Answer

Initial concentration of SO3 = number of mol of SO3 / volume
= 0.640 mol / 4.50 L
= 0.142 M

Final concentration of O2 = number of mol of O2 / volume
= 0.200 mol / 4.50 L
= 0.0444 M

ICE Table:

                    [SO3]               [SO2]               [O2]              

initial             0.142               0                   0                 

change              -2x                 +2x                 +1x               

equilibrium         0.142-2x            +2x                 +1x               

Given at equilibrium,
[O2] = 0.0444
+1x = 0.0444
x = 0.0444
Equilibrium constant expression is
Kc = [SO2]^2[O2]/[SO3]^2
Kc = (+2x)^2(+1x)/(0.142-2x)^2
Kc = (+2*0.0444)^2(+1*0.0444)/(0.142-2*0.0444)^2
Kc = 0.124
Answer: 0.124

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