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owLV2 | Online teaching >G sjc cengagenow.com/ilrn/takeAssignment takeCovalent Activity do?locator-assignment take&takeAssignmentSessionLocator;=assignment take ::: Apps Can as 'CengageNow n @ MyMathLab Pearso Webadvisor @ Pearson REVEL English-101c a Rentals Cart D Formula name searc Wolfram Alpha Nuclear Chemistry- Introduction-Chapter 19 [Review Topics] 1. Radioactivity 3 pts M Uise the References to access important values if needed for this question. 2 Nuclear Reaction: identity Decay R3pts What is the binding energy in kJ/mol nucleons for lithium-6? k/mol nucleons 3. Nuclear Reaction: Predict Decay Pr.. 3 ptsM 4 pts The required masses (g/mol) are: IH-1.00783 ;On= 1.00867: Li-601 500 5. Radionuclides in Medical Imaging 2 pts 6. Binding Energy 5 pts 2req Submit Answer Retry Entire Group 7 more group attempts remaini ng Question Question 0 Type here to search 1:57 PM 12/8/2017Explanation / Answer
The atomic mass of Li 6 is 6.015 amu. Calculate the nuclear binding energy of this
nucleus and the corresponding nuclear binding energy per nucleon
Mass number = 6
No. of protons = 3, then
Neutrons = Mass number – proton number = 3 protons and 3 neutrons are present
Mass of proton = 1.0078316
Mass of neutrón = 1.00867
Total mass = 3*1.0078316 + 3*1.00867= 6.0495048 amu
The mass defect:
6.015-6.0495048= -0.0345048 amu
Mass = 0.0345048/(6.022*10^23) = 5.729*10^-26 g or -5.729*10^-29 kg
Energy released (Einstein E = mC^2)
E = m*C^2 = -5.729*10^-29 * (3*10^8)^2 = -5.1561*10^-12 J
Nuclear binding energy = E = -5.1561*10^-12 J
Nuclear binding energy per nucleon
Nucleon = neutron + protons = 6
E per nucleon = E / nucleon =( -5.1561*10^-12)/( 6) = 8.593*10^-13 J/nucleon
change to kJ/mol = (6.022*10^23)/1000 = 6.022*10^20
Etotal =(8.593*10^-13)*( 6.022*10^20) = 517470460 kJ/mol
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