QUESTION 6 For the titration above, the concentration of sodium hydroxide was st

Question

QUESTION 6 For the titration above, the concentration of sodium hydroxide was standardized with potassium hydrogen phthalate. It took 12.14 ml of the sodium hydroxide solution to reach the equivalence point with 0.7083 g of potassium hydrogen phthalate. What is the concentration of the sodium hydroxide solution? QUESTION 7 What is the Ka of the acid used in the tration?If you use scientfic notation, you must enter a number such as 1 x 104 as 1t-4;otherwise, you can enter it in standard notation such as 0.0001.

Explanation / Answer

KHC8H4O4 + NaOH -------------> KNaC8H4O4 + H2O

no of moles of KHP = W/G.M.Wt

                                = 0.7083/204   = 0.00347moles

1moles of KHP react with 1 moles of NaOH

0.00347 moles of KHP react with = 1*0.00347/1 = 0.00347 moles of NaOH

no of moles of NaOH   = molarity * volume in L

0.00347                     = molarity * 0.01214

molarity of NaOH        = 0.00347/0.01214   = 0.2858M

Q7   Ka = 1.3*10^-3

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