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Question 1 (10 points) In the dissolution of urea experiment, a student dissolve

ID: 1030131 • Letter: Q

Question

Question 1 (10 points) In the dissolution of urea experiment, a student dissolves 1.2 g of urea into 25.4 mL of water. The initial temperature was 25.3 oC and the final temperature was 21.7 °C. Calculate qsys The specific heat of water 4.184. Your Answer: Answer Save Question 2 (10 points) Calcu late G° for the dissolution of urea when 4.4 g of urea dissolved in 4.4 mL of water at 2S °C, R-8.314 nmol,K Your Answer: Answer save Question 3 (10 points) Calculate asf AG-71.35 karmole and&H-93; kJ/moleat 2SHc Your Answer Answer

Explanation / Answer

(1)

Heat evolved by water = m*C*dT

Here, m = Mass of water = Density*Volume = 1*25.4 = 25.4 g

C = Specific heat capacity = 4.184 J/(g.C)

dT = Initial temperature - Final temperature

Putting values we get:

qsys = 25.4*4.184*(25.3-21.7) = 382.58 J

Hope this helps !

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