After answering these questions, enter your answers in Bb. The system has been s

Question

After answering these questions, enter your answers in Bb. The system has been setup for two attempts. If for any reason, the system fails, tear out the page and give this to your TA before prelab lecture starts. You are allowed up to two paper submission per semester. 1. Using a sample of 0.385 g of Alka-Seltzer, the mass of CO2 is found to be 0.122 g. Calculate and enter response (numerical value only) to three significant figures. a) The mass of NaHCOs that produced the 0.122 g of CO2. (1 pt) b) The % mass of NaHCO3 in the sample. (1 pt) c) The mass of NaHCO, in the tablet assuming the mass of the tablet is 3.50 g. (2 pts) 2. If based on the procedure described in the lab procedure, the data is Mass (before reaction): test tube + HCl(aq)+ stir bar+capsule Mass (after reaction): test tube+ HCI(aq)+ stir bar+capsule Volume of water displaced from the wash bottle Temperature of the CO2(g) CO-(g) pressure 26.042g 25.783 g 144 mL 293.6 K 0.986 atm Calculate each of the items below to three significant figures. Enter only the numerica value in the answer box. a) Calculate the mass of CO2(g) (1 pt) b) Calculate the moles of COa(g) (1 pt) c) Calculate the density of CO2(g) in g/L(1pt) d) Calculate the molar mass of CO2 assuming a temperature of 2936 K. (2 pts) CHEM 1210.LAB 8 Mass NaHCO, in Alka-Seltzer Tablet, Density of CO(g) Molar Mass of CO-(g), and the Ideal Gas Constant (R) 134

Explanation / Answer

1. Alka-Seltzer sample = 0.385 g

mass CO2 = 0.122 g

a) mass NaHCO3 that produced 0.122 g CO2 = (0.122 g/44 g/mol) x 84.01 g/mol = 0.233 g

b) % NaHCO3 in tablet = 0.233 x 100/0.385 = 60.52%

c) when tablet = 3.50 g, mass NaHCO3 = 0.233 x 3.50/0.385 = 2.120 g

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2.

a) mass CO2 = (initial - final) mass = 0.259 g

b) moles CO2 = PV/RT = 0.966 x 0.144/0.08205 x 293.6 = 0.0058 moles

c) density CO2 = 0.259 g/0.144 L = 18 g/L

d) molar mass CO2 = 0.259 x 0.08205 x 293.6/0.966 x 0.144 = 44.85 g/mol

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