The first-order decomposition of cyclopropane has a rate constant of 6.7 x 10-4

Question

The first-order decomposition of cyclopropane has a rate constant of 6.7 x 10-4 s-1. If the initial concentration of cyclopropane is 1.33 M, what is the concentration of cyclopropane after 644 s? The first-order decomposition of cyclopropane has a rate constant of 6.7 x 10-4 s-1. If the initial concentration of cyclopropane is 1.33 M, what is the concentration of cyclopropane after 644 s? The first-order decomposition of cyclopropane has a rate constant of 6.7 x 10-4 s-1. If the initial concentration of cyclopropane is 1.33 M, what is the concentration of cyclopropane after 644 s?

Explanation / Answer

for first order reaction

K = (2.303 /t) log [A0] / [A]

[A0] = 1.33 M , [A] = ?

t = 644 s

6.7 x 10-4 = (2.303 / 644) log [1.33] / [A]

0.187 = 0.124 - log [A]

log [A] = - 0.063

[A] = 0.86 M

final concentration = 0.86 M

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