For each of the reactions below: Translate from words to the appropriate chemica

Question

For each of the reactions below: Translate from words to the appropriate chemical formulas indicating the states for each substance. Balance the chemical equation with the appropriate coefficients. Write the molecular equation, ionic equation and the net ionic equation for each. Be sure to show all charges as well as states. In the ionic equation circle all spectator ions. If both products are aqueous salts the reaction will not proceed. For reactions like this, simply write N.R. (no reaction).

Aluminum metal reacts with a solution cadmium nitrite.

10. A 15.45 ml volume of 0.1327 M KMnO4(aq) is needed to oxidize 25.00 ml of a FeSO4(aq) in an acidic medium. What is molarity of the FeSO4(aq) given the following balanced net ionic equation:

5 Fe2+(aq) + MnO4-(aq) + 8H+(aq) ( Mn2+(aq) + 5Fe3+(aq) + 4H2O(aq)

Balance the following oxidation-reduction reaction by method of ½ reactions.

c) CN-(aq) + MnO4-(aq) ( CNO-(aq) + MnO2 [basic]

Explanation / Answer

9)

2Al(s) +3 Cd(NO3)2(aq) -------------------2 Al(NO3)3(aq)   +3 Cd(s)

2 Al(s) + 3 Cd+2(aq) + 6 NO3-(aq) ------------- 2 Al+3(aq) + 6 NO3-(aq) + 3 Cd(s)

spectator ion is NO3-

2 Al(s) + 3 Cd+2(aq) -------------- 2 Al+3(aq) + 3 Cd(s)

10)

5 Fe2+(aq) + MnO4-(aq) + 8H+(aq) --------------- Mn2+(aq) + 5Fe3+(aq) + 4H2O(aq)

5 moles        1 mole

              KMnO4                                        FeSO4

M1= 0.1327 M                              M2= ?

V1=15.45 mL                               V2= 25.00 ml

n1= 1 mole                                 n2= 5 mole

          M1V1/n1= M2V2/n2

0.1327x15.45/1 = M2x25.00/5

M2=0.410M

Molarity of FeSo4= 0.410M

c)

    CN-(aq)   + MnO4-(aq) ------------------- CNO-(aq)   + MNO2

   +2 -3          +7 -2                           +4 -3 -2          +4   -2

Oxidation half reaction

    CN- --------- CNO-

CN- + H2O ---------- CNO-

CN- + H2O + 2 OH- ------------ CNO- + 2 H2O

CN- + H2O + 2 OH- ----------- CNO- + 2 H2O + 2e-

Reduction half reaction

MnO4- ------------- MnO2

MnO4- -------------- MnO2   + 2 H2O

MnO4- + 4 H2O --------------- MnO2 + 2H2O + 4 OH-

MnO4-   + 4 H2O + 3e- --------- MnO2 + 2 H2O + 4 OH-

[CN- + H2O + 2 OH- ----------- CNO- + 2 H2O + 2e-] x3

[MnO4-   + 4 H2O + 3e- --------- MnO2 + 2 H2O + 4 OH-]x2

3CN- +3 H2O + 6 OH- -----------3 CNO- + 6 H2O + 6e

2 MnO4-   + 8 H2O + 6e- --------- 2 MnO2 + 4 H2O + 8 OH-

-------------------------------------------------------------------------------------------------

3 CN- + 2 MNO4- + 2H2O ---------------- 3 CNO- + 2 MNO2 + 2 OH-

-------------------------------------------------------------------------------------------------------

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.