3/23/2018 11 55 PM 95.8/100 3/22/201804:16 PM Question 24 ol 24 University Scien

Question

3/23/2018 11 55 PM 95.8/100 3/22/201804:16 PM Question 24 ol 24 University Science Books presented by Saping Leaming General Chemistry 4th Edtion Suppose that ind the esk containing nutrients for the bctria and that you t(min) Number of bacteria 17.0 34.0 51.0 68.0 100 200 400 800 1600 What is the order of the rate of production of the bacteria? How many bacteria will be present after 153 min? Number O zero order O frst order O second order bacteria What is the rate constant for the process? Number units Select answer O Previous Check Answer Net Ext

Explanation / Answer

Part a

On observing the given data, number of bacteria doubles after every 17 seconds. It gives a straight line on the graph.

Therefore it is of first order reaction

Part b

After 85 min,

The number of bacteria = 2*1600 = 3200

After 102 min,

The number of bacteria = 2*3200 = 6400

After 119 min,

The number of bacteria = 2*6400 = 12800

After 136 min,

The number of bacteria = 2*12800 = 25600

After 153 min,

The number of bacteria = 2*25600 = 51200

Part C

Rate constant for first order reaction

[A] = [A]o exp( –k(t))
[200] = [100] exp(–k(17))
2 = exp(–k(17))

0.6932 = - 17 k

k = –0.04 min–1

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