C Chegg.com 03433/take Question 4 5 p Excess amount of 6.0M NaOH was added to a

Question

C Chegg.com 03433/take Question 4 5 p Excess amount of 6.0M NaOH was added to a solution containing 3 metal cations and after stirring for enough time, a lab operator found that only one metal cation remained in solution whereas the other 2 cation were precipitated out. What would be the 3 metal cations? O A13+, Mg2+,Zn2+ O Zn2+, Fe3+,Cu2+ O Hg2+, Ag+, Cd2+ O AI13+, Mg2+,Cd2+ O Ba2+, Cu2+, A13+ Question 5 5 pt What will be the final molarity of HCI if 5.30 mL of 6.00M HCI was diluted to 25.0 mL volumetric flask? O 3.00M O 4.25M O 1.95M O 1.27M O 2.25M

Explanation / Answer

As 2 cations are solid and among the following option A is correct. Al(OH)3 Mg(OH)2 are solids where Zn(OH)2 is not.

Moles of HCl = Molarity x Volume (in L)

= 5.30 x 6 / 1000 moles

And final volume = 25 + 5.30 mL = 30.30 mL

So final molarity = moles / volume (in L)

M = 5.30 x 6 / 30.30 M

= 1.04 M

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