Trial 1: Room Temperature Temperature of saturated borax solution: Temperature o

Question

Trial 1: Room Temperature Temperature of saturated borax solution: Temperature of saturated borax solution: Volume of borax solution titrated: Concentration of HCI Volume of HCI used Moles of HCI used Moles of B40s(OH)4-2 present in titrant Concentration of B Os(OH)42 in titrant Concentration of Na* in titrant 230 c inhal:o 50m 8.0 ml 0.00m)moles 0.0000 moles Equilibrium Constant Ksp expression Calculated equilibrium constant value Trial 1: Cooled Solution Temperature of saturated borax solution: Temperature of saturated borax solution: Volume of borax solution titrated: Concentration of HCI Volume of HCI used Moles of HCI used Moles of B Os(OH)2 present in titrant Concentration of BaOs(OH)42 in titrant Concentration of Na* in titrant ml F: 31. 3 0.10M ml 0.00128 8moles 000040 moes Equilibrium Constant Ksp expression Ksp- Calculated equilibrium constant value TA Signature (Continued on Reverse Side) 18

Explanation / Answer

Na2B4O5(OH)4 <----> B4O5(OH)42- + 2Na+

So[ B4O5(OH)42- ]=1/2[Na+]=0.18M

[Na+]=2*0.18M=0.36M

ksp of borax= Na2B4O5(OH)4 =[B4O5(OH)42-] [Na+]^2=(0.18M) (0.18*2)^2=0.0233

ksp=0.0233

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