sotopes, determine the atomic number, the mass number, the number of protons ele
ID: 1033390 • Letter: S
Question
sotopes, determine the atomic number, the mass number, the number of protons electrons and neutrons. Isotope Atomic Symbol Number Number Protons Electrons Neutrons Name 53 226.90 131 131 He 24.0026 44 .9t PART 8 Complete the following chart by writing the symbol for the isotope of the following elements. In addition, give the number of protons, electrons, mass number and atomic number and complete the element name. Mass Element Neutrons Protons Number NumberSymbol Uranium- 145 28 Oxygen9 Boron- Beryllium-5 Carbon-Explanation / Answer
In the periodic table an element is represented in the following Symbol:
AZ Symbol of the Element or Mass numberAtomic numberSymbol of the Element
The same is named as Name of the element - Mass Number (A)
Where, The subscript, Z, the atomic number of any element, is same as the number of protons.
The superscript, A, the mass number of any element, is same as the number of protons + No of nuetrons.
The mass number and atomic number can be obtained from th periodic table.
The number of Electrons is same as number of protons (Z).
So if we consider the first example from the first table, the given symbol is
The atomic number Z is 53 ====> number of protons = number of electrons = 53
The Mass number A is 131====> number of protons + number of neutons = 131
====> 53 + number of neutons = 131 ====> number of neutons = 131 - 53 = 78
====> number of neutons = 78
The isotopic name is Iodine - 131
Similarly, example 1 from second table: Uranium -
It is given that the number of neutrons is 145.
One can obtain the atomic number Z from the periodic table. For uranium, atomic number Z is 92.
Therefore, number of protons is 92
Number of electrons = number of protons = 92
Mass Number (A) = Number of neutrons + Number of Protons = 145 + 92 = 237
The isotpic symbol would be AZ Symbol of the Element = 23792 U and
the isotopic name would be Uranium - 237
Similarly the rest of the examples can be solved:
and the second table is:
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