Copper metal slowly reacts with oxygen in the air to form a reddish copper (l) o

Question

Copper metal slowly reacts with oxygen in the air to form a reddish copper (l) oxide, Cu2O, which is a compound that coats the surface of older pennies and makes them look tarnished. When such a penny is place in a solution of salt in vinegar, the copper (l) oxide acts as a base and reacts with the vinegar to form copper salts. This effectively cleans the penny. the copper salts can then be transformed back into copper metal when exposed to an iron nail. 1. Are copper ions positively or negatively charged? 2. What is the charge on the copper atoms within the Cu2O? What is the charge on the oxygen? 3. What must copper ions gain in order to transform back into a metallic form? 4. What was the iron of the nail able to do for the copper ions?

Explanation / Answer

Answer:-

!. copper ions are positively charged.

2. Charge on the copper atoms in Cu2O = +1

charge on the oxygen atoms in Cu2O = -2

3. copper ions gain electrons in order to transform back into metallic form,

Cu+ + e- ------> Cu

4. The iron of nail is able to reduce the copper ions.

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