GRIGNARD REAGENT-SYNTHESIS OF BENZOIC ACID . AA Aav es New Ro?111 ,-, | .L??. He
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GRIGNARD REAGENT-SYNTHESIS OF BENZOIC ACID
. AA Aav es New Ro?111 ,-, | .L??. Heading 1 Heading 2 TNG Font Paragraph Reading Assignment - Watch the video tutorial on recrystallization Video-Recrystallization Goals and objectives of the experiment and the procedural in your laboratory notebook The procedural summary should include some or all of the following techniques summary should be written directly " o Measure o Distill o Calibrate o Extract o Filter/collect o Purify o Analyze o Characterization of using by to determine by NOTE: The examples of words given above are not comprehensive. You may use other appropriate terms. Do not use the words reactantireagent, product or solvent; write the name of the compound! Write the overall equation of the reaction. Pre-lab Questions 1. List the glass wares that must be dried in the oven 2. Prepare the physical properties table for the reagents and product 3. Write a flow scheme for the work-up. 4. Write the mechanism for the reaction. 5. The by-product in the reaction is biphenyl formed by the reaction of bromobenzene with m bromide. Wnte an equation for its formation Advance Preparatiorn Wash the required glasswaues and dry in an oven keptat 110-C for a minimum of one hour Wash epta and odher plastic items required and rinse with acetone Do not place them in the oven. Obtain a syringe and two needles from your instructor Pre-lab report is due at the beginning of the lab session. words inything 0?@??Explanation / Answer
1. Limiting reagent is the one which has less number of moles present in the reaction mixture.
Let's calculate number of moles for Mg and Ph-Br.
Molecular weight of Mg = 24 g/mol.
Weight of Mg = 100 mg.
Therefore, number of moles = 100/24 millimole = 4.17 millimole
Similarly, Molecular weight of Ph-Br = 157 g/mol
Weight of Ph-Br = 660 mg
Number of moles = 660/157 millimole = 4.20 millimole
Therefore, Mg is the limiting reagent.
Ether will not be considered as reagent, because it does not take part in the reaction mechanism and therefore it is just a solvent.
2. We assume that the reaction in part A has reached to completion.
That means 4.17 millimole of Mg has reacted with 4.17 millimole of Ph-Br to generate 4.17 millimole of Ph-Mg-Br.
From the chemical equation of part B, it is clear that 1 molecule of PhMgBr reacts with 1 molecule of CO2.
Therefore 4.17 millimole of CO2 is required to react with 4.17 millimole of PhMgBr.
Molecular weigh of CO2 = 44 g/mol.
Therefore, 4.17 millimole of CO2 = 44X4.17 = 183.48 = 184 mg.
3. Oxidation state of Mg metal is 0 and oxidation state of Mg in PhMgBr is +2. Therefore, Mg is oxidized and PhBr is reduced.
4. Unreacted Mg should react with HCl to form MgCl2.
Mg + HCl = MgCl2 + H2
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