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1 Consider the reaction, The part below is optional since it\'s only one questio

ID: 1033799 • Letter: 1

Question

1 Consider the reaction, The part below is optional since it's only one question 2.per chegg question, but if you do it, it will definitetly help me out and I will be sure to give you a thumbs up The ?G" for the reaction Citrate-isocitrate is 6.64 kJ mol-1 Glucose-6-phosphate+H20 Glucose+P Glucose][P] eq-Glucose-6-P] The ? G"for the reaction Isocitrate-a-Ketoglutarate is-267 kJ mol-1 The Keg at pH8.5 and 38 °C is 122. Can you determine the rate of the reaction from this information? What is the value of AG" for the reaction Citrate Ketoglutarate? A. No, the equilibrium constant provides the equilibrium position, not the rate of reaction. kJ mol1 B. Yes, the rate is the reciprocal of Kea 0.00820 in this case. C. . Yes, the rate is calculated as Keg divided by the temperature, Is the reaction Citratea-Ketoglutarate exergonic or endergonic when the reactant and product are at standard state concentrations? is needed to calculat the whe ucose 1 rate Endergonic 3.21 in this case. Exergonic

Explanation / Answer

Ans. #1. Rate of reaction, r = Keq [Glucose]n

            Where,

                        Keq = equilibrium constant at specified temperature

                        [Glucose] = Initial [Glucose]

                        n = order of reaction.

# Even if n = 1, the initial [Glucose] must be provided to calculate the value of rate of reaction, r.

So, correct option is – C. No, the concentration of glucose is needed to calculate the rate.

#2. Note: dG0’ for the conversion of Isocitrate into a-Ketoglutarate can’t be -267 kJ /mol (seems to a type error), it’s practically impossible under cellular conditions. So, calculation is made using dG0’ = -26.7 kJ/mol ; if needed you can follow the steps for the given value (dG0’ = -267 kJ/mol)

# The net reaction can be written as the sum/coupling of following two reactions-

            Citrate <--------> Isocitrate                                    ; dG0’ = +6.64 kJ/mol

            Isocitrate <-----> a-Ketoglutarate                         ; dG0 = -26.7 kJ/ mol

            ----------------------------------------------------------------------------

Citrate <------> a-ketoglutarate                             ; dG0’net = ?

# Since the dG0’ value of coupled reaction (dG0’net) is the sum of two coupled reactions.

So,

            dG0’net = 6.64 kJ mol-1 + (-26.7 kJ mol-1) = -20.06 kJ mol-1

# When dG0’ is negative, the reaction is exergonic.

Since the dG0’ is also negative, the conversion of citrate into a-ketoglutarate is also exergonic.