5. You zananre directed to administer 0.7 g of kanamycin sulfate using a mixture
ID: 1034246 • Letter: 5
Question
5. You zananre directed to administer 0.7 g of kanamycin sulfate using a mixture that contains $00 mg of 6. You are directed to administer 180 mg of cefuroxime axetil suspension. The label on the vial of cefuroxime axetil powder reads to reconstitute with distilled water to achieve a concentration of 0.12 g/5 mL. Shade in the volume of the reconstituted mixture you should administer. 7. What is the formula for the hydronium ion? 8. What is the formula for the hydroxide ion? What is the equation used to convert between the hydronium ion and hydroxide ion concentrations at 25 ?? 9. 10. What is the equation for calculating pH?Explanation / Answer
5) The concentration of kanamycin sulfate is 500 mg/mL. The dosage of kanamycin sulfate required is 0.7 g.
Volume of kanamycin sulfate required to achieve the dosage of 0.7 g = (0.7 g)/(500 mg/mL) = (0.7 g)/[(500 mg/mL)*(1 g/1000 mg)] = (0.7 g)/(0.5 g/mL) = 1.4 mL (ans).
6) Cefuroxime axetil powder has a concentration of 0.12 g/5 mL = (0.12 g/5 mL) = 0.024 g/mL.
The required dosage is 180 mg.
Volume of mixture that must be administered to achieve the desired dosage = (180 mg)/(0.024 g/mL) = (180 mg)*(1 g/1000 mg)/(0.024 g/mL) = (0.18 g)/(0.024 g/mL) = 7.5 mL (ans).
7) The hydronium ion is simply obtained by attaching a proton (positively charged hydrogen, H+) to neutral water (H2O). Therefore, hydronium ion is H3O+.
8) The hydroxide ion is obtained by remove a proton (H+) from water. Therefore, hydroxide ion is OH-.
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