Name D You Must show work on these pages&transter; your final answers to the ans
ID: 1034580 • Letter: N
Question
Name D You Must show work on these pages&transter; your final answers to the answer shheet providd Cooperative Learning for Exam 2 Spring 2018 M W 1. " the equilibrium constant for the reaction 2-4m + cou-CHOH.. in a mixture in which all species are initially 0.010 M? ¡s 1000, what wil happen a. Reaction goes to the right b. Reaction goes to the left No change occurs c. 2. The reaction equilibrium the reaction had produced 6.0 M Bra. 2NOB 2NO Brag) began with 18.0 M NOBr (and none of the products). At a. What is the value of the equilibrium constant K? b. What is the value of Kp for this reaction at 25°c? 3. If the equilibrium constant for the reaction 2 BrgBraig is 4.0, what is the each species present at equilibrium when 2.5 mol IBr is sealed in an empty flask amount of BrExplanation / Answer
1. For the reaction,
with initial concentration of all species = 0.010 M
Qc = [CH3OH]/[CO][H2]^2
= (0.010)/(0.010)(0.010)^2
= 10000
Qc > Kc, so,
b. reaction goes to the left
This would reduce Qc until Qc = Kc
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2. For the reaction,
at equilibrium,
[Br2] = 6.0 M
[NO] = 2 x 6.0 = 12.0 M
[NOBr] = 18 - 2 x 6.0 = 6 M
So,
a) Kc = [NO]^2.[Br2]/[NOBr]^2
= (12)^2 x (6)/(6)^2
= 24
b) Kp = Kc(RT)^dn
dn = 3-2 = 1
R = gas constant
T = 25 oC + 273 = 298 K
so,
Kp = 24 x 0.0821 x 298 = 587.2
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3. For the reaction,
Kc = [I2][Br2]/[IBr]^2 = 4.0
initial [IBr] = 2.5 moles
2IBr <===> I2 + Br2
I 2.5 - -
C -2x +x +x
E 2.5-2x x x
So,
4.0 = (x)(x)/(2.5-2x)^2
15x^2 - 40x + 25 = 0
x = 1 moles
so at equilibrium,
[IBr] = 2.5 - 2 x 1 = 0.5 moles
[I2] = 1 M
[Br2] = 1 M
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