the buffer base was a solid (FW of NaC2H3O2* 3H2O is 136 g/mole convert the gram

Question

the buffer base was a solid (FW of NaC2H3O2* 3H2O is 136 g/mole convert the grams of sodium acetate to moles of sodium acetate. Then calculate the molarity M, of sodium acetate (M= moles/L b) The buffer base was a solid (FW of NaC,H 0, 3H,O is 136 g/mole). Convert the grams of sodium acetate to moles of sodium acetate. Then calculate the molarity, M, of sodium acetate. (M-moles /L) The buffer acid was a liquid (3.0 M in the stock bottle). When you made the buffer solution, you diluted this stock solution of buffer acid. Calculate the new, diluted molarity of buffer acid in the buffer solution. c) d) Use the calculated molarities and the pKa to calculate the pH of this buffer 4. Caleulate the pH of the buffer after the addition of HCi added. The volume of buffer id was 1.0 mL. The total volume Take into account the dilution of the original buffer when the HCI solution was used for this part is (64.4 mL x ½-32.2 mL). The volume of the added ac of the buffer is now 33.2 mL a) pyright O 2015 Pearson Education, Inc.

Explanation / Answer

1) To find Molar mass of sodium acetate

Molar mass = C2H3NaO2= 2(12.01) + 3(1.008) + 22.99 + 2(16)

= 82.034 g/mol

2) Converting Sodium acetate gram to mol

Mol of C2H3NaO2 = 136 g/mol C2H3NaO2 * 1 M of C2H3NaO2/ 82.04 g/mol

= 1.65 mole

3) Calculate Molarity of Sodium acetate

Molarity = amount of solute (mole) / volume in litre

= 1.65 mol / 1 Litr

Molarity = 1.65 M

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