2.) A triprotic acid requires three moles of base to neutralize it, and the prot

Question

2.) A triprotic acid requires three moles of base to neutralize it, and the proton are removed one at a time as follows...

2) A triprotic acid requires three moles of base to neutralize it, and the protons are removed one at a time as follows: A titration curve, which plots the pli of the acid solution versus quantity of base that is added can reveal several things about the nature of t poi curve lution versus quantity of base that is added he acid. First, some or all of the equivalence can be observed in the graph as places where there is a maximum in the slope of the nts As an example, you have a 40.0 ml solution of a triprotic acid. H.A, with a concentration of 0.0588 M. You titrate it with a 0.250 M solution of NaOH. How many millimoles of H,A are you titrating? (Give units.) How many millimoles of NaOH are required to complete the titration? (Give units.) What volume of NaOH will be needed to completely titrate the acid? What volume of NaOH will be needed to reach the first equivalence point? What volume of NaOH will be needed to reach the second equivalence point?

Explanation / Answer

1. from the given eqautions 3 mole of base is required, in millimoles 3000 millimoles required( 1mole= 1000 millimole)

2. from the given data M1= 0.0588M, V1=40 ml, M2=0.250M , V2=? (volume of base)

now M1V1= M2V2

V2= (0.0588*40)/ 0.250

= 9.41 ml of NaOH is required to complete titration of acid

3. 1 mole of NaOH is required to reach first equivalance point

4. 2 moles of NaOH is required to reach second equivalence point. at this point 1 mole acid react with 2 moles base.( diprotic)

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