Homework 409 5 9.7 958734268 offsetanext C Homework 40 9.5, 9.7 and 9.8 ideal ve
ID: 1038230 • Letter: H
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Homework 409 5 9.7 958734268 offsetanext C Homework 40 9.5, 9.7 and 9.8 ideal versus Real Gases Comparison )23 ol24 eall versas real behavior for pases taw and also the wan der Waals equation Take note of how they affer ?PartA The idoal gas law describes the relationship among the volume of an ideal gas (V. ts pressure (P) its absolute temperature (T and number of moles (n) PV-RT Under standand conditions, the ideal gas law does a good job of approxmating these propertes for any gas.However the ideal gas law does not account for all the propertes of real gases such 1.00 mol of argon is placed in a 0 500-L container at 280 C, what is the ideal pressure cas predided by the ideal gas law) Express your answer to hree signicant ioures and include the appropriate unts. View Available Hins more pronounced atf low temperatures and high pressures The constants a and & which are unique to each substance Waals equation con corrects for ece tadors with The pas constant Ris equal to 0 08206 I atm/(K-mol) Po Value Units Submit PartB 100 moll of angon is placed in a 0 500-L. container at280 "C, what is the real pressure (as predicled by the van der Waals equabion)? For argon, a 1345 (L.3-t)/mol andb- 0.03219 L/mol Express your answer to three sigsiticant figures and include the appropriate units View Available Hints 010 e?? 10:00 PM E /3/2018 Type here to search ?Explanation / Answer
According to ideal gas equation,
PV = nRT
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = universal gas constant
T = absolute temperature
P * 0.5 = 1 * 0.0821 * (28+273)
P = 49.4 atm
According to vander waal's equation,
(P + a(n/V)^2)(V-nb) = nRT
(P + (1.345*(1/0.5)^2))(0.5-(1*0.03219)) = 1 * 0.0821 * (28+273)
P = 47.4 atm
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