Using the overall balanced equation for this lab found on page 4, What is the th

Question

Using the overall balanced equation for this lab found on page 4, What is the theoretical yield of alum KAL(SO4)2•12H20 if 1.2 grams of aluminum are completely reacted?
Using the overall balanced equation for this lab found on page 4, What is the theoretical yield of alum KAL(SO4)2•12H20 if 1.2 grams of aluminum are completely reacted?
4. Using the overall balanced equation for this lab found on page 4, what is the theoretical yield of Alum. (KASO 12H,O)if 12 grams of aluminum are completely reacted?

Explanation / Answer

The reactions of alum are given below,

2 Al + 2 KOH + 6 H2O ----> 2 K[Al(OH)4] + 3 H2

K[Al(OH)4] + 2 H2SO4 -----> KAl(SO4)2 + 4 H2O

KAl(SO4)2 (aq) cooled ------> KAl(SO4)2.12 H2O(s)

2 moles of Al produces 2 moles of K[Al(OH)4]

1 mole of Al produces 1 mole of K[Al(OH)4]

and 1 mole of K[Al(OH)4] produces 1 mole of KAl(SO4)2.12H2O solid.

hence,

1 mole of Al produces 1 mole of KAl(SO4)2.12H2O solid.

27g of Al produces 474.46 g of KAl(SO4)2.12H2O

1.2 g of Al produces 474.46/27 * 1.2 g of KAl(SO4)2.12H2O

mass of KAl(SO4)2.12H2O solid peoduced = 21.087 g

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