type your answer. answer ALL, show your work. thx Use the cotmpound bariae phesp

Question

type your answer. answer ALL, show your work. thx

Use the cotmpound bariae phesphate to answar the following questions: a Deemise the molecular welghi of he compound b. A studant soods 580 moles of the above compound how many grams mest he weigh out? e. A second stedent used 119 grans of the compound in an experiment. How mary moles did this repeesenc? d. What would be the per cent by welight of oxygen in the compound? If a soadest weighed out 678 grams of the compound how many sobal sdoms would be in the sample? e. f. If by mistake a student used the bexa bydrasted form of the above sah instead of the anhydrous form what would be the per cent water by weight in the hydrated form? 206

Explanation / Answer

Barium Phosphate = Ba3 (Po4)2  

1 MOLECULAR WEIGHT =233.305 GRAM/MOL

MOLAR WEIGHT= 601.92?g?mol?1.

B NUMBER OF MOLES= WEIGHT TAKEN IN GRAM / MOLECULAR WEIGHT

FOR .580 MOLES AND MOLECULAR WEIGHT =233.305 GRAM/MOL

WEIGHT TAKEN IN GRAM= NUMBER OF MOLES*MOLAR MASS

= .580 MOLES* 601.92?g?mol?1.

= 349.1136 GRAM

C

NUMBER OF MOLES= WEIGHT TAKEN IN GRAM / MOLAR MASS

WEIGHT TAKEN IN GRAM=189

MOLECULAR WEIGHT= 601.92?g?mol?1.

NUMBER OF MOLES= 189/601.92

=0.313 MOLES  

D

% by mass of OXYGEN = number of oxygen *Mass of OXYGEN*100% /Formula mass of barium phosphate

The formula mass of Ba3(PO4)2 is 601.92?g?mol?1.

number of oxygen=8

If we require the % composition by Oxygen  content, the calculation is:

8*16 g?mol/1601.92?g?mol?1*100% = .21*100 = 21%  

e  

1 mol= 6.023*1023  atom

67.8 gram/601.92 gram mol-1 = 0.113 mol

0.113 mol =  0.113 mol*6.023*1023  atom

=68.06*10 21 atom

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