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For the following reaction between Mohr\\\'s salt (iron as FeSO4(NH4)2SO4·6H2O)

ID: 1039269 • Letter: F

Question

For the following reaction between Mohr's salt (iron as FeSO4(NH4)2SO4·6H2O) and potassium dichromate (dichromate as K2Cr2O7), determine the volume (in milliliters) of a 0.130 M solution of Mohr's salt that is needed to fully react with 0.0200 L of 0.130 M potassium dichromate. (The reaction is shown in its ionic form in the presence of a strong acid.)

For the following reaction between Mohr's salt (iron as FeS04(NH4)2SO4 6H2O) and potassium dichromate (dichromate as K2Cr207), determine the volume (in mililiters) of a 0.130 M solution of Mohr's salt that is needed to fully react with 0.0200 L of 0.130 M potassium dichromate. (The reaction is shown in its ionic form in the presence of a strong acid.) Number Mohr's salt volume-L mL For the same reaction, what volume (in milliliters) of 0.130 M potassium dichromate is required to fully react with 0.0200 L of a 0.130 M solution of Mohr's salt? Number potassium dichromate volume mL

Explanation / Answer

from equation :

   1 mol Cr2O7^2- = 6 mol Fe^2+

no of mol of K2cr2o7 taken = 0.02*0.13 = 0.0026 mol

no of mol of Fe2+ required = 0.0026*6/1 = 0.0156 mol

volume of mohrs salt consumed = n/M

                   = 0.0156/0.13

                  = 0.12 L

                  = 120 ml

no of mol of Fe2+ taken = 0.02*0.13 0.0026 mol

no of mol of K2cr2o7 consumed = 0.0026*1/6 = 0.000433 mol

volume of K2Cr2o7 consumed = n/M

                          = 0.000433/0.13*1000

                          = 3.33 ml

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