1. Oxidation of 1g carbohydrate, fat and protein yields 0.56, 1.07, and 0.42 g m
ID: 1039297 • Letter: 1
Question
1. Oxidation of 1g carbohydrate, fat and protein yields 0.56, 1.07, and 0.42 g metabolic water respectively. Retention of 1g of dietary protein yields 0.16 g metabolic water whereas 0.07g of water is prduced when 1 g of dietary fat and carbohydrate, respectively, are retained as fat.
For a lactating cow consuming 15 kg DM/day and feed contains 76% carbohydrate, 4% fat, and 14% crude protein;
How much metabolic water will the cow produce under the following scenarios:
(i) If 65% of carbohydrate, 70% fat, and 60% crude protein is oxidized?
(ii) If 15% of crude protein, 15% fat, and 12% carbohydrate is retained?
Explanation / Answer
15 kg DM contains,
carbohydrate = 76% of 15 kg = 15000 * (76/100) g = 11400 g
fat = 4% of 15 kg = 15000 * (4/100) g = 600 g
protein = 14% of 15 kg = 15000 * (14/100) g = 2100 g
i) The amount of metabolic water will produce,
on oxidation of 65% of carbohydrate is = (65/100) * 11400 * 0.56 g = 4149.6 g
on oxidation of 70% of fat is = (70/100) * 600 * 1.07 g = 449.4 g
on oxidation of 60% of protein is = (60/100) * 2100 * 0.42 g = 529.2 g
ii) The amount of metabolic water will produce,
on retention of 15% of protein is = (15/100) * 2100 * 0.16 g = 50.4 g
on retention of 15% of fat is = (15/100) * 600 * 0.07 g = 6.3 g
on retention of 12% of carbohydrate is = (12/100) * 11400 * 0.07 g = 95.76 g
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