6.606.5 g of potassium contains how many moles of potassium atoms? A) 31.02 mole
ID: 1039917 • Letter: 6
Question
6.606.5 g of potassium contains how many moles of potassium atoms? A) 31.02 moles K B) 2.371 x 104 moles C) 1.186 x 104 moles K D) 7.756 moles K E) 15.51 moles AB) none of these 7. What is the mass of sixteen fluorine atoms? A) 1.69 x 10-20 g F 3.73 x 1022 g F D) 1.69 x 1021 g F B) 3.73 x 1021 g F C) E) 3.37 x 1021 g AB) none of these 8. How many atoms are in 4.70 moles of Co? C) 7.80 x 1024 atoms Co A) 7.80 x 1024 atoms Co B) 1.67 x 1026 atoms D) 2.83 x 1024 atoms Co E) 4.80 x 1022 atoms 0 AB) none of these 9. What is the molar mass of C402Hs? A) 88.10 g C402Hs C402Hs B) 120.12 g C) 29.02 g C4O2Hs D) 76.11 g C4O2Hs E) 102.12 g C4O2Hs AB) none of these 10. What is the mass percent of carbon in C4O2Hs? A) 55.42 mass % C B) 40.89 mass % C) 40.90 mass % C D) 52.54 mass % C E) 54.52 mass % AB) none of these
Explanation / Answer
Answer:
(6) Given mass of potassium (K)=606.5 g
Molar mass of K=39.0983 g/mol
We know that number of moles=mass/molar mass
Moles of K=606.5 g/39.0983 g/mol=15.51 moles of K.
(E) is correct option.
(7) Given 16 fluorine (F) atoms,
We know that 1 mole contains 6.023x10^23 atoms.
For 16 F atoms=? moles
Moles of 16 F atoms=(1 molex16 atoms)/(6.023x10^23 atoms) =2.656x10^-23 moles.
Molar mass of fluorine=18.998 g/mol
Mass of 16 F atoms=2.656x10^-23 moll x 18.998 g/mol=5.046x10^-22 g of F.
Option (AB) none of these are correct.
(8) We know that from Avogadro's law
1 mole=6.023x10^23 atoms.
Given 4.70 moles of CO contains how many atoms.
=(4.70 mol x 6.023x10^23 atoms)/1 mole
=2.83x10^24 atoms CO.
(D) is correct option.
(9) The molar mass of C=12.01 g, H=1.0079 g, and O=15.999 g.
The molar mass of
C4O2H8=4x(12.01g)+2x(15.999 g)+8x(1.0079 g)
=88.10 g C4O2H8.
(A) is correct option.
(10) Mass of 4C=4x12.01 g=48.04 g.
Mass of C4O2H8=88.10 g
(%) Carbon=(mass of C/total mass)x100
=(48.04 g/88.10g)x100=54.52 mass%.
(E) is correct option.
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