This question has multiple parts. Work all the parts to get the most points. For

Question

This question has multiple parts. Work all the parts to get the most points. For the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0.245 mol of the first reactant. AgNOs (ag) + LiOH(aq) - AgOH(s) + LiNO3(aq) g AgOH g LiNO3 bFor the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0.135 mol of the first reactant. Al2 (SO4)s(aq) + 3CaCl2 (ag) - 2AICls (aq) +3CaSO4(s) g AlClg g CaSO4 For the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0 245 mol of the first reactant. CaCO3(s) 2HCl(a)CaCl2 (aq) CO2(9) H20() g CaCl2 Previous Next g CO2

Explanation / Answer

a) AgNO3(aq) + LiOH(aq) ------------> AgOH(s) + LiNO3(aq)

according to balanced reaction

1 mole AgNO3 gives 124.88 g AgOH

0.245 moles AgNO3 gives 0.254 x 124.88 /1 = 31.72 g AgOH

mass of AgOH formed = 31.72 g

1 mole AgNO3 gives 68.95 g LiNO3

0.245 moles AgNO3 gives 0.245 x 68.95 / 1= 17.51 g LiNO3

mass of LiNO3 formed = 17.51 g

b) according to balanced reaction

1 mole Al2(SO4)3 gives 2 x 133.34 g AlCl3

0.135 moles Al2(SO4)3 gives 0.135 x 2 x 133.34 / 1 = 36.0 g AlCl3

mass of AlCl3 formed = 36.0 g

1 mole Al2(SO4)3 gives 3 x 136.14 g CaSO4

0.135 moles Al2(SO4)3 gives 0.135 x 3 x 136.14 /1 = 55.14 g CaSO4

mass of CaSO4 formed = 55.14 g

c) 1 mole CaCO3 gives 110.98 g CaCl2

0.245 moles CaCO3 gives 0.245 x 110.98 / 1 = 27.15 g CaCl2

mass of CaCl2 formed = 27.15 g

1 mole CaCO3 gives 44 g CO2

0.245 moles CaCO3 gives 0.245 x 44 / 1 = 10.78 g

mass of CO2 formed = 10.78 g

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