of the moles of solute per liters of solution. The M for a solution can be calcu
ID: 104073 • Letter: O
Question
of the moles of solute per liters of solution. The M for a solution can be calculated using the following equation: molanity, Af, of a solution is the molar in moles of solute = liters of solstion of a solution is known, an be used as a conversion factor to find ether the number of moles of solude when the volume of the solution s known or Once the the volume of liquid required when the number of moles of the solute is known. Given the number of moles of solute, the mass of the solute can then be calculated using the molar mass of the solute: mass solute in sample (moles solute in sample) X When using unit factors, make sure that like units cancel, leaving you with the units you want 28. 1 pt 29 Ch Part A How many milliters of 12.0 M hydrochlonic acid contain 8.55 g of HC1 (36.46 g/mol) solute? Express your answer to three significant figures with the appropriate units Hints 30. t So 1 pt 31. ± Sold SubnitMy Answers aive Up 1 pt 32 Basics of Part B What volume of 7.00 M hydrochloric acid contains 10.5 g of HCI (36.46 g/mol) solute? Express your answer to three significant figures with the appropriate units. Hints 34. Exeroise 13 84Explanation / Answer
Part-A
Molarity = M= 12.0M
mass of solute = 8.55 grams
Molar mass of HCl= 36.46 gram/mole
number of moles of solute = mass/molar mass = 8.55/36.46 = 0.2345 moles
Molarity = numbe of moles of solute/volume inL
Volume in L = number of moles of solute/Molarity = 0.2345/12.0= 0.01954 L
Volume in mL= 19.54 mL
Volume in mL= 19.5mL
part-B
molarity = 7.0M
mass of solute = 10.5 grams
molar mass of HCl= 36.46 gram/mole
number of moles of solute = 10.5/36.46 = 0.288 moles
volume of HCl= 0.288/7.0 = 0.0411 L
Volume of HCl in mL= 41.1 mL
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