Solid manganese (II) carbonate is put pure water and an equilibrium is establish

Question

Solid manganese (II) carbonate is put pure water and an equilibrium is established. The Ksp for MnCO3 is known to be 5.0*10^-10.What is the concentration of CO3^2- ions in the equilibrium mixture of MnCO3 ake/launchjsp?course assessment id 109879 1& course id- 25632 1acontent id- 1220608 18. rcbc.blackboard.com/webapps/as Pricelinecom TripAdvisor ? Imported ftom IE For the following balanced equation, indicate the oxidation number for each element in each substance: (Use whole numbers without any spaces before or after the number. If the number is positive, do not use the (+) sign, if the answer ??negative use the (-)sign before the number, no space between Each answer is worth 2 points ) 2 V20s (s) 4V (s)502 (g) The oxidation number tor v n v205 is [ The oxidation number tor O in V20s is The oxidation number for V in V is The oxidation number for O in o2 t QUESTION 12 10 points For the folowing redox reaction, which element is oxidized and which element is reduced? How many electrons are irwolved with the balanced reaction? 2 V205 (s)4V (s)502(9) ? V is oxidized and oxygen s reduced, 10 electrons are involved with re balanced reaction V is oxdized and oxygen s reduced, 20 electrons are involved with he Dalanced reaction Ov is reduced and oxygen is oxidized, 20 electrons are involved with the balanced reaction V is reduced and oxygen is axisized. 15 elections are involved with the balanced reaction Cliok Save and Submit to sase and mubmi Click Sae alil Anmsers to sqve all arsuours Save

Explanation / Answer

Ksp = [Mn+2][CO3-2]

Ksp = s2 = 5×10-10 => s = 2.24×10-5 M

Oxidation number of V in V2O5 = 5

Oxidation number of O in V2O5 = -2

Oxidation number of V in V = 0

Oxidation number of O in O2 =0

Answer 12

V is reduced and O is oxidized ,20 elections are involved with the balanced reaction

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