final solution. The terms M and M2 are often expressed in molarity, M, which is

Question

final solution. The terms M and M2 are often expressed in molarity, M, which is equal to mol/L. Another way to write the equation is to replace subscripts of 1 and 2 with abbreviated notations representing concentrated and diluted, as follows 1 is the Based on the inverse nature of this equivalency, small volumes of concentrated solutions can be used to prepare large volumes of diluted solutions with a known concentration, which is advantageous in areas involving solution chemistry Part A n order to understand how this equation is derived and why it holds true, the product of each side of the equation should be examined. What value and unit do you get when you multiply a concentration of 0.754 M by a volume of 0.500 L? This question can be expressed as O L x 0.754 mol = Express your answer to three significant figures with the appropriate units M,v,= 1 Value Units Submit My Answers Give Up When you need to produce a variety of diluted solutions of a solute, you can dilute a series of concentration of the given solute (typically 10 to 10 times prepared using minimal amounts of the stock solution stock solutions. A stock solution has a significantly higher han those of the diluted solutions). The high concentration allows many diluted solutions to be vnat volurme of a 6.13 Mlock solution do you need to prepare 250 Iml. f a o oso0s Af solution ot HENO, 29. c Express the volume to three significant figures with the appropriate units. 1 pt Hints 30. 1 pt Value Units

Explanation / Answer

M1 = 0.754M = 0.75mole/L
V1 = 0.5L
M1V1 = 0.75mole/L*0.5L
      = 0.375moles
part-B
before dilution                 after dilution
M1 = 6.13M                      M2 = 0.0505M
V1 =                            V2 = 250ml
       M1V1   = M2V2
          V1 = M2V2/M1
              = 0.0505*250/6.13   = 2.06ml >>>>answer
part-A
    M1V1 = M2V2
      M2   = M1V1/V2 >>>>answer
part-B
before dilution                after dilution
M1 = 46.3%(m/v)                M2 = 22.4%
V1 = 0.903L                    V2 =
    M1V1 = M2V2
      V2 = M1V1/M2
          = 46.3*0.903/22.4   = 1.86L   = 1860ml >>>answer

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