Answer the following questions based on the reaction below. At 277 K, the rate c
ID: 1040969 • Letter: A
Question
Answer the following questions based on the reaction below. At 277 K, the rate constant for this reaction is 6.36 /s and at 652 K the rate constant is 1.42×105 /s.
methoxyethane ? methane + ethanal
1. Determine the activation energy (EA) (in kJ/mol) for this reaction. Report your answer to three significant figures in scientific notation.
2. Determine the pre-exponential factor, A (in /s) for this reaction. Report your answer to three significant figures in scientific notation (Please carry all the digits for EA calculated in part 1).
3. Determine the rate constant (in /s) for this reaction at 1338 K. Report your answer to three significant figures in scientific notation (Please carry all the digits for A calculated in part 2).
Please answer all parts!
Explanation / Answer
1.
Arrhenius integrated equation is,
ln(k2/k1) = ( Ea / R ) * [( 1 / T1 ) - ( 1 / T2 ) ]
ln(1.42 * 105 / 6.36) = ( Ea / 0.008314 ) * [ ( 1 / 277 ) - ( 1 / 652 ) ]
Ea = Activation energy = 40.1 kJ/mol
2.
Arrhenius equation,
k = A * e(-Ea/RT)
6.36 = A * e[-40.1 / (0.008314 * 277)]
A = 2.32 * 108 /s
3.
k = 2.32 * 108 * e[-40.1 / 0.008314 * 1338)]
k = 6.31 * 106 /s
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