Jump t... /8/2018 11:55 PM A 37.8/1004/6/2018 0941 PM Gradeb stion 6 of 29 In Sa
ID: 1041049 • Letter: J
Question
Jump t... /8/2018 11:55 PM A 37.8/1004/6/2018 0941 PM Gradeb stion 6 of 29 In Sapling Learning Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X more readily reacts to form a cation descriptions by Xsalt bridge Y whether they apply to the X or Y electrode. X electrode cations from the salt bridge flow toward loses mass electrons in the wire flow away from cathode Y electrode electrons in the wire flow toward anions from the salt bridge flow toward gains mass anode x (ad) Y2" (aq) Since X is more lkely to formi cations,it is more likely to be oxidized Oxidation occurs at the anode Previous incorrect Give Up & View Solution Thy AgainExplanation / Answer
X electode
Acording to the given data
X acts as anode, at anode oxidation reaction takesplace
M(s)-------------- M+n(aq)+ ne-
So inthe anodic half cell more cations are present so balance the positive
charge negaive moves from the saltbridge towords tothe anodic halfcell,
Anode can looss the mass.
electrons moves from the anodic to cathode through a wire.
It can acts as ANode.
Y electrode
Y electrode acts as cathode
M+n(aq) + ne- ----------- M(s)
Electons reachig the cathode from the anode.
cation are converts to neutral metal atom.so more anions are present.
so the balance charge the positive ions moves towords to this from salt bridge.
mass is gained and deposite on the cathode.
It is cathode.
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