n.a. Stock Concentration (M) x Maximum Absorbance. a1 Wavelength at Max 518.40?0

Question

n.a. Stock Concentration (M) x Maximum Absorbance. a1 Wavelength at Max 518.40?04.40|-1(X,40 Absorbance (nm) N...N Distance (pm) 3 10q1284 153 251.5 230 211.5 650114 14523 3 41 d (pm) p (pm) n.a. max mol.cm Dye chosen for Beer's law plot: blue bi o4 40 nm max: solution stockx10 1.202 2:1 dilution00 0,90 max (Beer's law plot): 2903moleen mol.cm ilution 14.0x10-? 10,099 1:2 dilution | 3.0 X 10-b |0,459 Questions Are the p values you calculated reasonable, based on the structures of the dyes? That is, what about the structure of the dyes might lead to a "lengthening" of the orbital? 1.

Explanation / Answer

The lengthening of orbital can be attributed to the conjugation.

Higher the conjugation lower the length of bond.

As the conjugation order is

Dye III > DYE II > DYE I

and the p value order is

DYE I > DYE II > DYE III

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.