The vapor pressure of liquid ethyl acetate, CHCOOc2Hs, is 100. mm Hg at 300 K A
ID: 104137 • Letter: T
Question
The vapor pressure of liquid ethyl acetate, CHCOOc2Hs, is 100. mm Hg at 300 K A sample of CH CooC2H is placed in a closed, evacuated 510 mL container at a temperature of 300 K. It is found that all of the CHCOOCH is in the vapor phase and that the pressure is 59.0 mm Hg. If the volume of the container is reduced to 360 mL at constant temperature, which of the following statements are correct? Choose all that apply. Liquid ethyl acetate will be present. The pressure in the container will be 100. mm Hg. No condensation will occur Some of the vapor initially present will condense O Only ethyl acetate vapor will be present.Explanation / Answer
Answer;
given that
case 1
ethyl acetate placed in closed container, volume = 510ml, T = 300K and vapour pressure = 59 mm Hg
use ideal gas equation
PV = nRT
0.0776316 atm * 510 ml = n * 0.0821 L-atm/deg-mole * 300K ( 1 mm Hg = 0.00131579 atm)
n1 = 1.607 moles of ethyl acetate
case 2
volume(V2) = 360 ml at constant temperature.
we follow boyle's law
at constant temperature
P1V1 = P2V2
0.0776316 atm * 510 ml = P2 * 360 ml
P2 = 0.1099781 atm = 83.5833440922 mm Hg.
therefore n2 = P2V2 / RT
n2 = 0.1099781 atm * 360 ml / ( 0.0821 L-atm/deg-mole * 300K)
n2 = 1.607 moles of ethyl acetate
we observed that as we decrease the volume of a container the pressure is increasing while moles of ethyl acetate remain same that means we pressuring the ethyl acetate externally. as we increase the pressure the molecules come closer to each other, The attractive forces eventually become strong enough to hold the molecules close together, and the gas condenses to the liquid state.
So,
the liquid ethyl will be present.
the pressure in the container will be 83.5833440922 mm Hg.
condensation will occur.
some of the vapor initially present will condense.
ethyl acetate vapor and also liquid will be present.
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