Consider a different titration for this exercise. Potassium permanganate (KMnO4)
ID: 1041856 • Letter: C
Question
Consider a different titration for this exercise. Potassium permanganate (KMnO4) is the titrant and hydrogen peroxide (H202) the analyte according to the following balanced chemical equat (a) What is the stoichiometry of M to H202 8:3 5:2 1:2 10 2:5. 3:8 (b) Complete the following table for this titration. Data Table P3: Titration of hydrogen peroxide with potassium permanganate concentration of Mno volume H202 solution mass H202 solution volume of Mno solution mmol of Mno mmol of H202 mass of H20 mass % of H2O2 in the original sample 0.559 M 7.79 ml 17.87 5.66 mL 8.75 mmol molarity of H,02 in the original sample 2 492MExplanation / Answer
2MnO4- + 5H2O2 +6H+ ---------> 2Mn+2+5O2+8H2O
Molar ratio of MnO4- and H2O2 is 2:5
So 2 millimoles of MnO4- require 5 millimoles of H2O2
8.75 millimoles of MnO4- ---? 8.75x5/2 = 21.875 millimoles of H2O2 = 0.021875 moles
mass of H2O2 :
no. of millimoles of H2O2 = wt taken/mol mass = 0.021875
x/34.01 =0.021875
x= 0.74397 gms'
mass % of H2O2 in the original sample = (mass of H2O2 /mass of H2O2 solution) x100 = (0.74397/17.87) x100 = 4.16%
Molarity of H2O2 = No. of moles/vol in lts = 0.021875/0.01787 = 1.22 M
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