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Consider a different titration for this exercise. Potassium permanganate (KMnO4)

ID: 1041856 • Letter: C

Question

Consider a different titration for this exercise. Potassium permanganate (KMnO4) is the titrant and hydrogen peroxide (H202) the analyte according to the following balanced chemical equat (a) What is the stoichiometry of M to H202 8:3 5:2 1:2 10 2:5. 3:8 (b) Complete the following table for this titration. Data Table P3: Titration of hydrogen peroxide with potassium permanganate concentration of Mno volume H202 solution mass H202 solution volume of Mno solution mmol of Mno mmol of H202 mass of H20 mass % of H2O2 in the original sample 0.559 M 7.79 ml 17.87 5.66 mL 8.75 mmol molarity of H,02 in the original sample 2 492M

Explanation / Answer

2MnO4- + 5H2O2 +6H+ ---------> 2Mn+2+5O2+8H2O

Molar ratio of MnO4- and H2O2 is 2:5

So 2 millimoles of MnO4- require 5 millimoles of H2O2

8.75 millimoles of MnO4- ---? 8.75x5/2 = 21.875 millimoles of H2O2 = 0.021875 moles

mass of H2O2 :

no. of millimoles of H2O2 = wt taken/mol mass = 0.021875

x/34.01 =0.021875

x= 0.74397 gms'

mass % of H2O2 in the original sample = (mass of H2O2 /mass of H2O2 solution) x100 = (0.74397/17.87) x100 = 4.16%

Molarity of H2O2 = No. of moles/vol in lts = 0.021875/0.01787 = 1.22 M

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