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6. Silver nitrate, AgNO3, can be used to test for the presence of chloride ions

ID: 1042237 • Letter: 6

Question

6. Silver nitrate, AgNO3, can be used to test for the presence of chloride ions in solution, because it readily forms a precipitate of AgCl. What volume of 2.0 M AgNO, will be required to react with 50.0 mL of a 0.10 M HCI solution? AgNO3(aq) + HCI(aq)- AgCl(s) + HNO3(aq) 7. Write the correct equilibrium constant expression for the following reaction: H,(g) +1,(g) 2HI(g) If the equilibrium concentrations are [HI] -1.0 M, [H2]-0.10 M, [Ch]-0.10 M, what is the value of the equilibrium constant? Are reactants or products favoured? 8. List the acid, base, conjugate acid, and conjugate base for the following reaction: HOCl (ag)H20OC (a) HO* (a 9. What are the products of an acetate ion, CH3Co, reacting with water? 10. If the pH of a coffee sample is 5.15, what is the hydronium ion concentration in the coffee? 11. Given an OH concentration of 1.0 x 10 M, calculate the H,0' concentration and then identify the solution as acidic, basic, or neutral.

Explanation / Answer

6.

AgNO3 (aq.) + HCl (aq.) -----------> AgCl (s) + HNO3 (aq.)

Moles of HCl = molarity * volume in L = 0.10 * 50.0 / 1000 = 0.00500 mol

From the balanced equation,

1 mol of HCl needs 1 mol of AgNO3.

SO, 0.00500 mol of HCl needs 0.00500 mol of AgNO3

Volume of AgNO3 needed = moles / molarity = 0.00500 / 2.0 = 0.00250 L = 2.50 mL of AgNO3

7.

Kc = [HI]2 / [H2][I2]

Kc = (1.0)2 / (0.1)(0.1)

Kc = 100

8.

Acid = HOCl

Base = H2O

Conjugate acid = H3O+

Conjugate base = OCl-

9.

CH3COO- (aq.) + H2O (l) = CH3COOH (aq.) + OH- (aq.)

Acetic acid and hydroxide ion

10.

pH = 5.15

- Log[H3O+] = 5.15

[H3O+] = 7.08 * 10-6 M

11.

[OH-] = 10-6 M

[H3O+] = 1.0 * 10-14 / 10-6

[H3O+] = 1.0 * 10-8 M

Since [H3O+] < 10-7, the solution is basic.

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