6. Silver nitrate, AgNO3, can be used to test for the presence of chloride ions
ID: 1042237 • Letter: 6
Question
6. Silver nitrate, AgNO3, can be used to test for the presence of chloride ions in solution, because it readily forms a precipitate of AgCl. What volume of 2.0 M AgNO, will be required to react with 50.0 mL of a 0.10 M HCI solution? AgNO3(aq) + HCI(aq)- AgCl(s) + HNO3(aq) 7. Write the correct equilibrium constant expression for the following reaction: H,(g) +1,(g) 2HI(g) If the equilibrium concentrations are [HI] -1.0 M, [H2]-0.10 M, [Ch]-0.10 M, what is the value of the equilibrium constant? Are reactants or products favoured? 8. List the acid, base, conjugate acid, and conjugate base for the following reaction: HOCl (ag)H20OC (a) HO* (a 9. What are the products of an acetate ion, CH3Co, reacting with water? 10. If the pH of a coffee sample is 5.15, what is the hydronium ion concentration in the coffee? 11. Given an OH concentration of 1.0 x 10 M, calculate the H,0' concentration and then identify the solution as acidic, basic, or neutral.Explanation / Answer
6.
AgNO3 (aq.) + HCl (aq.) -----------> AgCl (s) + HNO3 (aq.)
Moles of HCl = molarity * volume in L = 0.10 * 50.0 / 1000 = 0.00500 mol
From the balanced equation,
1 mol of HCl needs 1 mol of AgNO3.
SO, 0.00500 mol of HCl needs 0.00500 mol of AgNO3
Volume of AgNO3 needed = moles / molarity = 0.00500 / 2.0 = 0.00250 L = 2.50 mL of AgNO3
7.
Kc = [HI]2 / [H2][I2]
Kc = (1.0)2 / (0.1)(0.1)
Kc = 100
8.
Acid = HOCl
Base = H2O
Conjugate acid = H3O+
Conjugate base = OCl-
9.
CH3COO- (aq.) + H2O (l) = CH3COOH (aq.) + OH- (aq.)
Acetic acid and hydroxide ion
10.
pH = 5.15
- Log[H3O+] = 5.15
[H3O+] = 7.08 * 10-6 M
11.
[OH-] = 10-6 M
[H3O+] = 1.0 * 10-14 / 10-6
[H3O+] = 1.0 * 10-8 M
Since [H3O+] < 10-7, the solution is basic.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.