2. Answer the following questions about acetylsalicylic acid, the active ingredi
ID: 1042557 • Letter: 2
Question
2. Answer the following questions about acetylsalicylic acid, the active ingredient in aspirin. (a) A solution containing 0.955 grams of an unknown compound is vaporized in a 450. mL container at b) Elemental analysis of this unknown compound yields the following percentages by weight H-9.74%; (c) Complete combustion of a 1.05 gram sample of the compound with the stoichiometric amount of 0.988 atm and 78°C. Calculate the molecular weight of the compound. ? 38.70%; 0-5 1.56%. Determine the molecular formula for the compound. oxygen gas produces a mixture of H.0@ and Coe. What is the pressure of this gas mixture when it is contained in a 3.00 liter flask at 127°C?Explanation / Answer
a) using equation PV= nRT, where n represents no. Of moles = given it/ molecular wt
.988× (450/1000lt) = (.955/x)×.0821×
351. So molecular weight comes out be 61.8 g
b) to solve. This question we will be following certain steps.
Step1 ) divide the given percentages of all the elements by their molecular mass:
C= 38.70/12= 3.225
H= 9.74/1= 9.74
O= 51.56/16= 3.2225
Step 2 ) divide the number obtained by the smallest number out of the 3 i.e . 3.2225
C= 3.225/3.2225= 1
H= 9.74/3.2225= 3
O= 3.2225/3.2225= 1
So the empirical formula : CH3O
Molecular weight / emperical formula weight= 61.8/31= 2
Multiply 2 × the emperical formula,so molecular formulae= 2× CH3O= C2H6O2
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