tion 6 of 10 Sapling Learning A hot lump of 113.5 g of an unknown substance init

Question

tion 6 of 10 Sapling Learning A hot lump of 113.5 g of an unknown substance initially at 175.4 C is placed in 35.0 mL of water initially at 25.0 C and allowed to reach thermal equilibrium. The final temperature of the s ystem is 86.7 ? What is no heat is lost to the surroundings. O Zinc O Titanium O Graphite O Rhodium O Aluminum O Tungsten Substance Specific Heat (Jig-C)) 0.897 Aluminum Graphite Rhodium Titanium 0.709 0.243 0.523 Tungsten0.132 0.388 4.184 Zinc Water O Previous 0 Check Answer Next Exit 80 F3 ooo FA FS F7 F8 3 4

Explanation / Answer

M1 X C1 X Change in T1= M2 X C2 X Change in T2

35 * 4.186* (86.7-25)=113.5 * C2* (175.4-86.7)

Hence C2= 0.89791

Hence the unknown substance is Aluminium.

4.186 is the Specific heat capacity of water

For water, 1 mL= 1 gram

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