Given the data for the titration of a water/HCl solution with 0.1M NaOH I unders

Question

Given the data for the titration of a water/HCl solution with 0.1M NaOH

I understand the equivalence point is the point of rapid change in the pH but I don't know exactly what to pick as that point

Answer:

Volume of NaOH added at equivalence point?

pH at the equivalence point?

pH when solution showed persistent pink color (not sure about this one)?

Concentration of original HCl solution? (10mL of HCl in 50ml water)

5 2 8 6 ? 3-37 816 8 3-00 5 9 99 1 6 60 722 28 12-38-094|12| 7 24 0 | 222|29| 5 072 2 68-04 4 3 00112599909200 8 les 11 17 25 33 44 61 86 56 678 10 12 12 765 99 1 4 1 2|34| 6 8 7-4 6-0 44|44| 4 4 5-6 6-7 80-2 2 534444 99999101020012 1010111 1 23|4 5-6 7 8-9 01|2 3-4-5 22-2 2-2 22-2

Explanation / Answer

1. volume of NaOH added at equivalence point is 10.4ml, at this volume pH value jump with larger variation ( 10.97-8.90= 2.07).this is the equvilence point.

2. pH at equivalence point is 10.97.

3.HCl concentration can be calculated from the formula M1V1=M2V2

here assume that M1=HCl concentration, V1=10 ml, M2= 0.1 (NaOH concentration), V2= 10.4 ml ( from graph).

now M1= M2V2/V1

= (0.1*10.4)/10

= 0.104M is the concentration HCl

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