1.Starting with 6.0 g of salicylic acid, how many grams of acetylsalicylic acid

Question

1.Starting with 6.0 g of salicylic acid, how many grams of acetylsalicylic acid (theoretical yield) can be made? Assume salicylic acid is the limiting reagent and a one to one stoichiometry. Use the molecular weights that you have already calculated. Give two significant digits.

2. Starting with 6.0 mL of acetic anhydride with a density of 1.082, how many grams of acetylsalicylic acid (theoretical yield) can be made? Assume acetic anhydride is the limiting reagent and a one to one stoichiometry. Use the molecular weights that you have already calculated. Give two significant digits.

Explanation / Answer

Answer:

1. From salicylic acid to acetylsalicylic acid,

We have 1:1 conversion.

The molecular weight of Salicylic acid is 138.121 g/mol. So number of moles of salicylic acid in the 6.0 g of salicylic acid is = 6/138.121 = 0.04344 moles

Hence salicylic acid be the limiting reagent. We will get equimolar of acetylsalicylic acid. The molecular weight of salicylic acid is 180.157 g/mol

Hence amount of acetylsalicylic acid should form = 180.157g/mol×0.04344 moles = 7.8062 grams (theoretical yield).

2. Similarly the density of acetic anhydride is 1.08g/cm3 or 1.08g/mL.

Volume of acetic anhydride taken = 6 mL

Amount if acetic anhydride = 6mL×1.08g/mL = 6.48 grams

The molecular weight of acetic anhydride is 102.09 g/mol.

Moles of acetic anhydride available for the reactions are = 6.48g/102.09g/mol = 0.06347 moles

So the amount of acetylsalicylic acid should form = 180.157g/mol×0.06347 mol = 11.4345 grams (theoretical yield).

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