se the titration curve of a weak acid with a strong base through (vii) deatisy t

Question

se the titration curve of a weak acid with a strong base through (vii) deatisy the Equivalence Point of Tirasion and label i on the titration curve below Titration Curve (oxalic acid/NaOH) 14 12 10 ar 6 4 2 0 Pcid 0 5 10 15 20 25 30 35 40 45 Volume of NaOH added (ml) (ii) What is the Titrant NaOHstrong base From the graph, what is the [H'1 and the volume of NaOH used to reach the equivalence point. pH-3 pH (iii) -log CH (iv) Calculate the IOH1 at the equivalence point (v) What is the pKa of the acid used for titration?

Explanation / Answer

At the equivalence point, moles of acid= moles of base. Hence from Henderson-Hasselbalch equation

pH= pKa+ log [Conjugate base]/[Acid]

[Conjugate base]= [Acid]

pH= pKa=8

pKa= 8,

Ka= 10(-pKa)= 10(-8)

Kb= 10-14/Ka= 10-14/ 10-8 = 10-6

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