I can\'t figure out (d) and the sig figs for (c) please help! A key step in the

Question

I can't figure out (d) and the sig figs for (c) please help!

A key step in the metabolism of glucose for energy is the isomerization of glucose-6-phosphate (G6P) to fructose-6-phosphate (F6P) as shown below. G6P F6P At 298 K, the equilibrium constant for the isomerization is 0.510.

(a) delta G° at 298 K. ANSWER=1.67 kJ/,mol

(b) Calculate G when Q, the [F6P]/[G6P] ratio, equals 11.0. kJ/mol ANSWER= 7.61 kJ/mol

(c) Calculate G when Q = 0.400. ANSWER is -0.600 but the sig figs are wrong so if you could help with that, i'd appreciate it.

(d) Calculate Q in the cell if G = -3.90 kJ/mol.

Explanation / Answer

c)

Answer : - 0.60 kJ/mol

here the delta Go = 1.67 kJ/mol . it has 2 digits after decimal place.

in the addition and substraction , the resulting answer should be rounded to least decimal places. here 2 digits after decimal place. so answer should be = - 0.60 kJ/mol

d)

delta G = delta Go + RT ln Q

- 3.90 = 1.67 + 8.314 x 10^-3 x 298 x ln Q

Q = 0.106

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