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Question

Safari File Edit View Bookmarks Window Help ??1D0% 150 Sun Apr 15 11:01 AM Q, E apinglearning.cemm ? Univarsity af Kentucky -CHF 113 Lat-SringR-FRENCH:iu-Lab 18 A solution containing a mixture of metal cations was treated with dilute HCl and a precipitate formed. The solution was filtered and H2S was bubbled through the acidic solution. A precipitate again formed and was filtered off. Then, the pH was raised to about 8 and H2S was again bubbled through the solution. This time no precipitate formed. Finally, the solution was treated with a sodium carbonate solution, which resulted in formation of a precipitate. Which metal ions were definitely present, which were definitely absent, and which may or may not have been present in the original mixture 100 95 80 95 Detinitely absent Possibly present 100 93 90 100 100 Previous Give Up & View Solution Check Answe Next Exit

Explanation / Answer

Treatment with dilute HCl gives precipitate, so, first group cation(s) defenetly present because first group cations forming insoluble chlorides.

so, Hg22+, Pb2+ and Ag+ possibly present

Treatment with acidic H2S gives precipitate, so, second group cation(s) defenetly present because these cations forming insoluble sulphides

So, Cd2+, Hg2+, Sn2+ and Bi3+ possibly present

Treatment with basic H2S gives no precipitate, so, fourth group cations are defenetly absent

so, Al3+, Fe2+ and Zn2+ are defenetly absent

Treatment with sodium carbonate gives precipitate, so, fifth group cation(s) defenetly present because these group cations forming insoluble carbonates

so, Ca2+, Mg2+ possibly present

sixth group cations analysis is not done, so, K+ may or may not present

Therefore, the conclusion is

Cations defenetly absent: Al3+, Fe2+ and Zn2+

Cations possibly present: Hg22+, Pb2+, Ag+, Cd2+,Bi3+,Hg2+, Sn2+, Mg2+ and Ca2+

Cations may or may not present : K+

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