https://ncia.wwnorton.com/10796 86% 04/17/18 This is a Numeric Entry question/It

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https://ncia.wwnorton.com/10796 86% 04/17/18 This is a Numeric Entry question/It is worth 4 points/You have 8 of 10 attempts remaining/There is no attempt penalt Question 4 points) The water-gas shift reaction is an important source of hydrogen. The value of K, for the reaction below is is 5.1 at 700 K Co g) H,0(Co)H(g) 16 3rd attempt il See Period Part 1 (1point) Calculate the equilibrium concentrations of the four gases if the initial concentration of each of them is O 111 M co-0034 Part 2 (1point) ico.1-077 Part 3 (1 point) See Part 4 (1 point) 2nd attempt

Explanation / Answer

          CO(g)   +   H2O(g)   <====> CO2(g) + H2(g)
initial 0.111 M       0.111 m             -        -

change    - x          -x                +x       +x

equil    0.111-x     0.111-x             x         x

Kc = [CO2][H2]/[CO][H2O]

5.1 = (X*X)/(0.111-X)^2

X = 0.077

at equilibrium,

[CO] = 0.111-0.077 = 0.034 M

[H2O] = 0.111-0.077 = 0.034 M

[CO2] = X = 0.077 M

[H2] = X = 0.077 M

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