How I can calculate grams of MgO sample? cations ofssmples Mass (g) | % Purity 0

Question

How I can calculate grams of MgO sample?

cations ofssmples Mass (g) | % Purity 0.9061 100.40292.2501:01250.00 | Ratio Rx. Stock Vol (mL) Conc (M) 0.01245 10 Sample FW (g/mol) 11 EDTA 12 MgSO1.6098 13 MgO 14 Table 2. Ttration data 010 250.00 120.37 40.31 MgO Aliquots (mL) EOTAYBUANK Vol EDTA 16 Sample Vol MgOVEDTA)VE (corr) 17 Blank0.003.90 10.00 19 U21000 20U3 210.00 22US 37.75 36.20 37.10 37.20 36.90 10.00 10.00 33.00 U6 10.00 36.90 24 25 26 Table 3. Titrimetric Resuts Unknowns 28 29 Sample mol MgO g MgO g MgOmoia Blank 0 000E+000000+00 00000 NIA #ON/10: 14215E-04 1699E-02 4.022E-04 1621E-02 4.134E-041.666E-02 4.146E-041 1.671E-02 5 4.109E-04 1656E-02 4.109E-041.656E-02 #DIV/0! #ON//0! Average RSD (ppth

Explanation / Answer

The calculation should be done by the knowledge of complexometric titration. As we know that edta will form 1:1 complex with Mg, therefore from the volume measurement of standard edta solution, we can calculate the amount of MgO as follows:

First we consider the average value of volume of edta required and which will be, ~ 33.058

V (edta) x S (edta) = V (MgO) x S (MgO)

33.058 x 0.01245 = 10 x S (MgO)

or, S (MgO) = 0.0411 M

Hence, 1.656 g (molar strength x FW) of MgO is there in 1000 mL of solution.

So, in 250 mL solution there will be 0.414 g of MgO present.

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