Q 1 Indicate with (more), (less), or (no change in) what you would expect the ac
ID: 1045925 • Letter: Q
Question
Q 1 Indicate with (more), (less), or (no change in) what you would expect the activity of an enzyme to under the following conditions: Addition of a competitive inhibitor C More C Less C No Change in Q2 Indicate with (more), (less), or (no change in) what you would expect the activity of an enzyme to do under the following conditions: Increase in temperature of 10°C (from 5°C to 15°C) C More C Less C No Change in Q 3 Indicate with (more), (less), or (no change in) what you would expect the activity of an enzyme to do under the following conditions: Change in pH from 5.0 to 1.0 ? More C Less C No Change in Q 4 Indicate with (more), (less), or (no change in) what under the following conditions: Decrease in substrate concentration C More you would expect the activity of an enzyme to do Less C No Change in Q5 Indicate with (more), (less), or ( under the following conditions: Protonation of an enzyme's amino acid not involved in the che C More no change in) what you would expect the activity of an enzyme to do Less C No Change inExplanation / Answer
1) Activity of an enzyme after an addition of competitive inhibitor is less. They alter the catalytic action of the enzyme and consequently slow down and in some cases they stop catalysing which can be explained by lock and key mechanism.
2) Activity of an enzyme increases for increase in temperature of 10o C (from 5o c to 15o c). For every 10o c increase in temperature will increase the activity of an enzymes by 50-100% as it increases the kinetic energy/vibrational energy of the molecules.
3) Activity of an enzyme decreases for change in pH from 5.0 to 1.0. Every enzyme have a specific optimum pH i.e pH at which the enzyme activity will be maximum. Every enzyme has different optimim pH. Based on optimum pH the change in pH alters the enzyme activity. A change in pH leads to decrease in enzyme activity because shape of the enzyme molecule will be disrupted and shape of the enzyme site will be changed.
4) Activity of an enzyme decreases for decrease in substrate concentration as the less substrate molecules collide with enzyme molecules and decreases the enzyme activity
5) Activity of an enzyme increases for protonation of enzyme's aminoacids because the charge of H+ ions are able to interfere with hydrogen bonds and teritiary structure of enzyme. The R group of amino acid is an active site. The concentration of H+ ions will change the charge site of the active site. These H+ ions woud attract the towards any negatively charged group that are in active site. These H+ ions are therfore attractedto groups and clusters around them. This alters the binding of substrate to the the enzyme active site
6) The enzyme where its name identifies is dehydrogenase (DHase). It is an enzyme which belongs to oxidoreductase that oxidise the substrate by reducing an electron acceptor like NADH, FAD/FMN etc
7) Km is equal to substrate concentration at half of the velocity maximum. If V0 = VMAX
then VMAX /2 = VMAX[substrate]/Km+[S] i.e Km +[S] = [2S] or Km = [S]
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