Use the References to access important values If needed for this question. An el

Question

Use the References to access important values If needed for this question. An electrochemical cell consists of a PtH (aq, 1.00 M)I12(8) cathode connected to a PijH (aq)IH2(8) anode in which the H concentration is that of a buffer consisting of a weak acid, HA(0.152 MM, mixed with its conjugate base, A-(0.187 M). The measured cell voltage is E cell = 0.247 V at 25 °C, with PH, -1.00 atm at both electrodes. Calculate the pit in the buffer solution and the K, of the weak acid. Ka Submit Answer 5 question attempts remaining

Explanation / Answer

Ecell = Eo + 0.05916 pH

Eo = 0

Ecell = 0.05916 pH

pH = Ecell / 0.05916

    = 0.247 / 0.05916

pH = 4.18

pH = pKa + log [A- / HA]

4.18 = pKa + log [0.187 / 0.152]

pKa = 4.09

Ka = 8.13 x 10^-5

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