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Safari File Edit View History Bookmarks Window Help ? 55%? Sun 11:40 PM a - ug.cengagenow.com ?? MtyConcordia - Concordia University NelsonBrain - Login or Register OWLv2 | Onlire teaching and learni... A Study Of Climbers Who Reached.. Chegg Study Guided Solutions an Chem 205 (A&B;) OWL Gases assignment Question 19 Question 20 ,pt Question 21 1pt Question 22 1pt Question 23 1pt Question 24? 1pt Question 25?1pt Quest!on 26?1pt Question 27 ? 1pt Question 28 1pt Question 29 Question 30 Iron forms a series of compounds of the type Fe,(CO In air, these compounds are oxidized to FeOs and CO gas. Ater heating a 0.158-8 sample of Fe,(CO)y ar, you isolate the CO2 ina 150-L flask at 25 °C. The pressure of the gas is 46.6 mm Hg What is the empirical formula of Fe(Co),? Fee(CO) Submit Answer Try Another Version 4 item attempts remaining not 57 PM not 35 PM Question 31 Question 32 Question 33 1 pt ) 1 pt Question 34 1pt 3 28/34 items Due Apr 16 at 11:55 PM Previous Next Finish Assignment Save and Exit

Explanation / Answer

Calculated the mole of CO2 using the pv=nRT and we got the mole to be 0.00376mol
using that I calculated the mass of CO2 to be 0.166g which is also equal to the mass of CO

mass of Fe=0.166-0.158g=0.0075g

Moles of CO will be equal to moles of CO2 but not the masses.
Using simple atomic masses CO= 28g/mol and CO2 = 44g/mol
Using these values , 0.00376 mol of CO will weigh 0.00376 x 28 = 0.10528g CO

So mass of Fe = 0.158 - 0.10528 = 0.0527g

Element/group Fe CO
Mass (g) 0.0527 0.10528
Moles 0.0527/56 0.10528/28
Ratio 9.412 x 10-4 0.00376
Divide by smallest 1 3.99
1 4
Fe(CO)4

So answer is Fe(CO)4

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