Using Hess\'s Law to calculate net reaction enthalpy There are two steps in the

Question

Using Hess's Law to calculate net reaction enthalpy There are two steps in the usual industrial preparation of acrylic acid, the immediate precursor of several us water react to form acetylene and calcium hydroxide: CaC2(s) + 2H20(g)--C2H2(g) + Ca(OH)2(s) ??--414. In the second step, acetylene, carbon dioxide and water react to form acrylic acid: 6C2H2(g) + 3CO2(g) + 4H20(g)-5CH2CHCO2H(g) ?? 132. kJ Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, wat Round your answer to the nearest kJ. kJ Check MacBook Air

Explanation / Answer

step1

write the given equations

(I) CaC2(s) + 2H2O(l) ====? C2H2(g) + Ca(OH)2(s) ?H= ?414.kJ - equation 1

(II) 6C2H2(g) +3CO2(g) + 4H2O(g) =? 5CH2CHCO2H(g) ?H =132.kJ - equation 2

step 2

Multiply equation (I) by 6 and the ?H by 6, then add the two equations:

6CaC2(s) + 12H2O(l) ==? 6C2H2(g) + 6Ca(OH)2(s) ?H= 6(?414.kJ) = ?H = -2484 kJ

6C2H2(g) +3CO2(g) + 4H2O(g) =? 5CH2CHCO2H(g) ?H =132.kJ
---------------------------------------...

6CaC2(g) + 16H2O(l) + 3CO2(g) =? 5CH2CHCOOH(g) + 6Ca(OH)2(s) ?H = -2352 kJ

step 3

we got -2352kJ/5 moles acrylic acid .

so Enthalpy of formation of acrylic acid = -2352kJ/5 = -471 kJ/mole acrylic acid

ANSWER= -471 KJ/MOL ACRILIC ACID

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